i got 93.08 percentile in jee mains 2020 with stands around 53k rank ( 7.6lac student attended jee mains act to yt) now with this percentile shall i get nit ( any branch) , btw im general, thankyou in advance
Hello Student
93.08 percentile in jee mains is not so hopeful percentile marks to get NITs for engineering course of study. To get top NIT student has to secure at least 99 to 98 percentile of marks in jee mains examination. As you have got 93. Jio percentage of marks and your rank season around 53000, so there is a little hope of chance to get top NITs. Gate of NITs student should achieve the rank of 15000 to 20000.
Hope this will help.
I am currently in 11th std ,when should I give SAT or ACT exam ?
Hey applicant!!
Now since you are pursuing your 11th Standard, you can prepare really well as it is the best time for you to utilise your time and seat for the exam, next comes your best preferable time to appear is in the month of November when you don't have much study pressure on your head, and before your finals you will have idea regarding the possible questions and how to answer them,
Hope it helps!!!
Find the magnitude of the two forces, such that if they act at right angles, their resultant is 10 N . But if they Act at 60, their resultant is root13 N .
Hello Priya,
Let us assume two forces F1 and F2.
In the question , there are two conditions given and accordingly we need to solve the equations by forming two equations.
In the first condition, the angle between two forces is 90 degree so apply the formula for the resultant which is =
F1^2 + F2^2 +2F1F2 *cos 90 = 10^2 - - - (i)
In the second condition the equation will come out to be :-
F1^2 + F2^2 + 2 F1F2 cos 60 = (√13)^2 - - - 2
So from the first get the value of F1 in terms of F2 and substitute in the second equation and a quadratic equation will be formed.