Hi,

The two forces of magnitude 24 and 7 units act at right angle.

The vector law :

Let P and Q be two vectors acting simultaneously at a point and  θ be the angle between P and Q and R be the resultant vector.

R² =P² +2PQcosθ+Q²   (magnitude)

= tan ^{- 1} ((Qsinθ/(P+Qcosθ))

Here magnitudes are 24 adn 7. θ=90°

So

The resultant of the two forces will be :

1. Magnitude : √ (24² )+(7² )= √ (576+49)= √ 625=25 units.

2. Direction; Suppose the vectors are 24i+7j, then the direction of the resultant will be:

= tan ^{- 1} (7/24) in radian.

Hope this helps!

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Hello, hope you are doing well!

Suppose your particle is at origin and you are applying force P and 2P from any side, and if the first force(P) is doubled it will become 2P and if second force is (2P)  is increased by 20N it will become become 2P+20N. Now the resultant would be same or unaltered only when the ratio of (P and 2P) would be equal to the ratio of (2P and 2P+20P).

That is (P/2P)=(2P/(2P+20)) => 1/2=(2P/(2P+20)) => 2P+20P=4P => 2P=20 => P=10. so, the value of P comes out to be 10N, and That is your answer.

Thank you

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Hello aspirant,

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Hope it helps!

Hello,

In the question it is stated that to be in equilibrium .In equilibrium their sum should be equal to zero .

So F1+F2+F3=0

2i+j-k+2i+3j-3k+ai+aj-ak=0

(4+a)i+(4+a)j-(4+a)k=0i+0j+0k

If we compare on both the sides

a=-4

Hope this answers helps!

Hello.,

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Hope this helps. Good luck

Hey there!

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Hello,

Yamini,

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Thank you.

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